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Precalculus
- Thread starter greyshrop
- Start date
Please show some work first so that we may help you with where you are stuck and read the rules for posting here: http://www.freemathhelp.com/forum/threads/41538-Read-Before-Posting!!Write the quadratic function that has x-intercepts at x=-2 and x=6. Find the x and y coordinates of the vertex of the function you wrote. Is it concave up, concave down, or neither?
I have no work to show. My teacher is awful and I don't understand anything we've learnedPlease show some work first so that we may help you with where you are stuck and read the rules for posting here: http://www.freemathhelp.com/forum/threads/41538-Read-Before-Posting!!
As far as the vertex goes, at most that I can see that you can state about it with the information given is thatWrite > > > the < < < quadratic function that has x-intercepts at x=-2 and x=6. \(\displaystyle \ \ \ \) There is not enough information here to pin one down.
Find the x and y coordinates of the vertex of the function you wrote.
Is it concave up, concave down, or neither? \(\displaystyle \ \ \ \) <----- This question doesn't make sense.
> > If it is the graph of a parabola, and it's a quadratic function, then it can't be the choice "neither." < <
> > It must be either the first or the second type. < <
its x-coordinate is the average of the two x-values of the x-intercepts. That is, the x-coordinate of the vertex is 2.
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