Perimeter of a kite

pka said:
I hope that you know that if \(\displaystyle a~\&~b\) are positive then \(\displaystyle \sqrt{ab}=\sqrt a\cdot\sqrt b~??\)
We know that \(\displaystyle UV=5~\&~XU=\sqrt{90}=\sqrt{9}\sqrt{10}=3\sqrt{10}\)
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So perimeter is incorrect?
 
rachelmaddie said:
I thought that the whole decimal of sqrt(90) was the exact value.
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It is absolutely impossible to give a decimal equivalent for \(\displaystyle 10+6\sqrt{10}\) that is an exact value.
Any decimal expression can only approximate the exact value.
 
pka said:
It is absolutely impossible to give a decimal equivalent for \(\displaystyle 10+6\sqrt{10}\) that is an exact value.
Any decimal expression can only approximate the exact value.
Click to expand...
P = 2 x 5 + 2 x 3sqrt10?
 
rachelmaddie said:
I thought that the whole decimal of sqrt(90) was the exact value.
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But the question is did you give the whole decimal number for sqrt(90)? The answer is you did not! You can't as the decimal number for sqrt(90) goes on forever with out repeating.
 
rachelmaddie said:
10 + 6sqrt10
= 28.97366596
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Are you serious? Put away your calculator, throw it out the window, smash it on the floor, but most importantly stop using it.
You had the exact answer but then you went and approximated it. Why would you do that?
 
Jomo said:
Are you serious? Put away your calculator, throw it out the window, smash it on the floor, but most importantly stop using it.
You had the exact answer but then you went and approximated it. Why would you do that?
Click to expand...
The exact answer is 10 + 6sqrt10?
 
rachelmaddie said:
3^2 + 4^2 = C^2
9 + 16 = C^2
C^2 = 25
Sqrt(25) = 5

3^2 + 9^2 = C^2
9 + 81 = C^2
C^2 = 90
Sqrt(90) = 9.48683298

P = 2 x 5 + 2 x 9.48683298
= 10 + 18.973666
= 28.973666
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Why do you have two different C2 with two different values and with same name? Change the variable names.
 
Jomo said:
Are you serious? Put away your calculator, throw it out the window, smash it on the floor, but most importantly stop using it.
You had the exact answer but then you went and approximated it. Why would you do that?
Click to expand...

Wow. Strong feelings towards her calculator.o_O
 
A kite is a quadrilateral with exactly two pairs of congruent consecutive sides.
To solve for the exact perimeter of the kite UVWX first apply the Pythagorean theorem by finding the lengths of the sides of the kite.
a^2 + b^2 = c^2
3^2 + 4^2 = c^2
9 + 16 = c^2
c^2 = 25
sqrt(25) = 5
The length of triangle UV is 5.
a^2 + b^2 = c^2
3^2 + 9^2 = c^2
9 + 81 = c^2
c^2 = 90
sqrt(90) = sqrt(9*10) = sqrt(9)*sqrt(10) = 3sqrt(10)
The length of triangle XU is 3sqrt(10).
P = 2a + 2b
P = 2(5) + 2(3sqrt(10))
P = 10 + 6sqrt(10)
The exact perimeter of kite UVWX is 10 + 6sqrt(10).
 
rachelmaddie said:
A kite is a quadrilateral with exactly two pairs of congruent consecutive sides.
To solve for the exact perimeter of the kite UVWX first apply the Pythagorean theorem by finding the lengths of the sides of the kite.
a^2 + b^2 = c^2
3^2 + 4^2 = c^2
9 + 16 = c^2
c^2 = 25
sqrt(25) = 5
The length of triangle UV is 5.
a^2 + b^2 = c^2
3^2 + 9^2 = c^2
9 + 81 = c^2
c^2 = 90
sqrt(90) = sqrt(9*10) = sqrt(9)*sqrt(10) = 3sqrt(10)
The length of triangle XU is 3sqrt(10).
P = 2a + 2b
P = 2(5) + 2(3sqrt(10))
P = 10 + 6sqrt(10)
The exact perimeter of kite UVWX is 10 + 6sqrt(10).
Click to expand...
What If I changed c^2 to UV^2 and XU^2?
 
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