Which of the following points lie on a line y=3x+4

Rabinov23

Rabinov23

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1569756918684.pngSorry for not presenting the work , but I just cant get it , can someone explain me the first one please in order to understand it.
I'm confused
 
Point (a, b) lies on the line if plugging in a and b satisfies the equation.
 
Plug in a for x and b for y, if you get a true equality then the point lies on the line.
 
So my last point is 0 which is y.
If we have y= in this case it will be o=4 because it is x in an equation and x is always first then 3 because it is x and 4 as it is y
 
Rabinov23 said:
So my last point is 0 which is y.
If we have y= in this case it will be o=4 because it is x in an equation and x is always first than 3 because it is x and 4 as it is y
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Yes, left side is 0, that's y. I don't understand how you are plugging in 4 for x. What do you get on the right side when x=4?
 
Rabinov23 said:
Can yo show what you mean?:)
please
Click to expand...
We will give you an example:

Find which of the following points lie on the line: y = 11*x + 12

[a] (1,2),

(0,12)

For [a] given x = 1

apply this to the given equation, we get,

y = 11*1 + 12 = 23 (NOT 2 as given)

So (1,2) Does not belong to the line.

For given x = 0

apply this to the given equation, we get,

y = 11*0 + 12 = 12 (yes.. 12 as given)

So (0,12) DOES belong to the line.
 
Rabinov23 said:
is b 4=0
Click to expand...
Again your answer Your answer b 4 = 0 does not make sense. "Zero" is never equal to "Four".

Please show your work/steps to explain how you are getting it! (as explained in response #15)
 
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