Dr.Peterson
Elite Member
- Joined
- Nov 12, 2017
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I give up. Go back and read what I've written, then think about it more.
YOU ARE NOT GETTING ANY INTEREST! THEY ARE.
YOU ARE NOT GETTING ANY INTEREST! THEY ARE.
okay suppose i am paying a installment of x to the bank at the end of first year then si gaining by the bank calculated will be on that year only?I give up. Go back and read what I've written, then think about it more.
YOU ARE NOT GETTING ANY INTEREST! THEY ARE.
This should be clear by now. They have the money from the first payment for four years, so they get 4 years of interest, not just 1.okay suppose i am paying a installment of x to the bank at the end of first year then si gaining by the bank calculated will be on that year only?
if uexplain me this line then thesum is over : Each amount paid earns simple interest from then until the end of the 5 years.
why will they have the money from 1st payment for 4 years? They can keep the payment as long as they want or can lend the amount to anyone. I have done my part of giving installment.This should be clear by now. They have the money from the first payment for four years, so they get 4 years of interest, not just 1.
@Dr.Peterson here u have said that the man will be getting interest. please be clearI think it's reasonably clear, if you know anything about interest and algebra. I don't think you've told us what you have learned, to give us a basis for knowing how to help -- if you had started by just quoting the answer and telling us what parts you don't understand, we could have saved a lot of time.
Here is what that person said:
Let installment = xSo after 1st year, we have paid installment of Rs. x so he will get an interest on this for next 4 years. Similarly , we have paid another installment of Rs. x at the end of years, so he will get an interest on this for next 3 years and so on.So (x + x*8*4/100) + (x + x*8*3/100) +(x + x*8*2/100) +(x + x*8*1/100) +(x ) = 580or 5x + x*8(1+2+3+4)/100 = 580or 5x + 80x/100 = 580or 5.8x = 580or x = Rs. 100So annual installment will be Rs. 100
The idea is that, with this method of payment, rather than keeping track of the balance, you just imagine the lender putting the money he receives in the bank so that it earns interest until the end, but at simple interest.
The first payment of x is made after 1 year, so it earns 4 years of interest until the end of the 5 years. The lender at the end gets x + x*8*4/100, that is, the principal x plus 8% of x times 4 years. I would have written this as x + 4*0.08x, or as x(1 + 4*0.08).
The second payment of x is made after 2 years, so it earns 3 years of interest, giving the lender x + x*8*3/100.
And so on. The total, (x + x*8*4/100) + (x + x*8*3/100) +(x + x*8*2/100) +(x + x*8*1/100) +(x ), has to equal 580, so you write an equation and solve for x. If you know a little algebra, this should be easy; but let us know if you struggle with the algebra.
Actually, the second "shortcut method" is trickier to understand, because it is explained badly. I was confused by reading that first and getting a wrong idea of how the payment method works. It supposes that each payment is 100, finds how much the lender would get after 5 years, and just scales it up. (This can be done because of the simple interest.) What is there called "first year" really relates to the last payment, which earns no interest. Then it works backward toward the first payment, which earns 4 years of interest.
The "formula method" just applies the same approach to a general problem with variables, using a formula for the sum of an arithmetic progression.
U are a mathematician u should dig deep and find out the process .I have nothing more to say until you can provide some evidence about how this loan works. The problem is not clear enough about such details. Find some source that explains it.
from people who tale loans@Dr.Peterson the bank is getting interest from whom? From other borrowers ?
thanksLet's calculate: (assume payment "x" rs/yr)
After 1 year Balance = 580*(1.08) - x
After 2 years Balance = 580*(1.08)^2 - x * (1.08) - x
After 3 years Balance = 580*(1.08)^3 - x * (1.08)^2 - x * 1.08 - x
After 4 years Balance = 580*(1.08)^4 - x * (1.08)^3 - x * 1.08^2 - x*1.08 - x
After 5 years Balance = 580*(1.08)^5 - x * (1.08)^4 - x * (1.08)^3 - x * 1.08^2 - x*1.08 - x = 0
Now solve for 'x' (see that term in GP)
This is a "non-mugging" (Indian term fot cramming) procedure.....
Go at it
anyone else?
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