J
JeffM
Guest
3. If I made a list of every seven-digit whole number greater than 1 million which has exactly six of its digits equal to 9, how many different numbers would be on my list?
62 is the correct answer, but your explanation is not very clear.The formula: 6 digits x9+ the greatest digit x8=62
Given a 7 digit number greater than 1 million and with exactly 6 digits equal to 9, how many places can you put the different digit?
7, obviously. The different digit can be in the first position, or the second, or the third .....
Ignoring the first position, how many digits different from 9 can you put into the position with the different digit?
9, namely 0 through 8.
So, ignoring the first position, the desired numbers = (7 - 1) * 9 = 6 * 9 = 54.
How many digits different from 9 can you put in the first position of a seven digit number and stay over a million?
8, namely 1 through 8, 0 does not work.
So the answer is 8 + 54 = 62.
Frequently explaining how you got your answer is just as important as the answer itself.
By the way, you should (1) ask 1 question per thread, (2) put puzzles under Odds and Ends (more people look there I suspect), and (3) make sure to explain that you are in fifth grade each time so that people will not give you some solution based on integral calculus or category theory