We keep going round and round the same issue.Ok, I didn't know that.
Thanks, that makes sense. I am close to dropping this issue.
Here is just one last idea that your summation equation made me think of. This is also my attempted proof.
Assumptions:
- Every natural number in increasing order is greater than the previous number by 1.
- There is an infinite number of natural numbers.
Conclusion 1:
- 1 is being added to a previous natural number an infinite number of times.
Final Conclusion:
- There must be an infinite natural number
That is all I got. If you find something wrong with that (and I understand you), I will finally be at peace with all this.
Let us say that the sum of an infinite sequence of 1’s is a number of some sort. (You understand, I hope, that a strict finitist would say that such a sum is a meaningless construct.)
You keep saying that such a sum x is a natural number. What are the definitionally required attributes of a natural number? Have you proved that x has each such attribute? If you have not defined what you mean by a natural number and logically proved that x satisfies the requirements, you are not justified in saying x is a natural number.
In fact, I can specify one of the attributes that I believe is necessary for a number a to be a natural number,
namely 2(a + 1) > a. But if x is a natural number, it is easily proved that 2(x + 1) = x. So I say that x is not a natural number.
In fact what I think you are doing is making an obvious error. There are many arithmetic operations on natural numbers that do not result in a natural number. 5 - 7. 7/3. sqrt(11). There is absolutely no a priori reason why adding up an infinite number of positive, natural numbers results in a natural number.