Trigonononometric Identities...

Oooh, I see. So C) works, sort of. But I got csc^2x minus cot^2x, not plus. Did i do something wrong?
 
frauleinedoctor said:
Wait a min, isn't [1 + cos^2] / [1 - cos^2] the same thing as the final answer you gave?

By Jove, it is!

Yours is just simplified more, right?

I would not say "more simplified"; I would just say "different".

So i wasn't alll that far off, right?

Are you asking this question in terms of the multiple choices you were given? :wink:
Click to expand...
 
frauleinedoctor said:
So C) works, sort of.

Not "sort of". It works, period.

But I got csc^2x minus cot^2x, not plus. Did i do something wrong?

You must have.

Oh, I see that I put a minus in my previous post, too.

So, I did something wrong, too.

What I did wrong is make a typographical error.

I'll go fix that right now.
Click to expand...
MY EDIT: Something seems to be wrong with my keyboard (heh, heh).
 
frauleinedoctor said:
THE ANSWER IS ONE ISN'T IT????!
Click to expand...


Good grief! :eek:

I already told you that the correct answer is C.

Why are you now thinking that it's D?

 
Ok, so its still C after all.

Ohh. So it was *both* of us. Ok. So how far down the line did that happen? Like what went wrong?
 
Ok. So, problem solved. Thank you so much for all of your help. I certainly learned a ton about how to use these identities. Thank you for your time, and ha, thanks for being patient.
 
frauleinedoctor said:
… Ohh. So it was *both* of us.
Click to expand...


I suppose so, since I did commit a typographical error.

(Did you copy my "error"? Is that where you went wrong? These are both rhetorical questions. My point is: let the buyer beware, if they quickly rely on other people's work without engaging their brain.)

However, in terms of walking the plank, I only inched a bit toward the end, whereas you appear to be teetering at the brink of disaster. :wink:

(You'll recover only after completing several of these types of exercises.)

If you would like to work on that other exercise, then please start a new thread.

 
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