The equation of line A is given by 2y − x = 6. 2 y minus x equals 6 Select the equation that could represent line B

[eddy2017]

i'm working on it.

Now, put the given equation for line A in the form y=mx+b :
[math]2y-x=6[/math][math]2y-x+x=x+6[/math][math]2y=x+6[/math][math]2y/2= (x+6)/2[/math][math]y=2x+3[/math]
the equation given has been converted to slope-intercept form.

 

[BigBeachBanana]

Now, put the given equation for line A in the form y=mx+b :
[math]2y-x=6[/math][math]2y-x+x=x+6[/math][math]2y=x+6[/math][math]2y/2= (x+6)/2[/math][math]y=2x+3[/math]-Incorrect

the equation given has been converted to slope-intercept form.

Not quite. Check your math again.

 

[Deleted member 4993]

Now, put the given equation for line A in the form y=mx+b :
[math]2y-x=6[/math][math]2y-x+x=x+6[/math][math]2y=x+6[/math][math]2y/2= (x+6)/2[/math][math]y=2x+3[/math]
the equation given has been converted to slope-intercept form.

last line is incorrect.

 

[eddy2017]

i'm working on it.

before I solve [math]3 + x/2[/math]I dont know where is that coming from and why you do that?

 

[eddy2017]

Not quite. Check your math again.

Can you checkmark where I went wrong?. I am not seeing the mistake.

 

[BigBeachBanana]

Can you checkmark where I went wrong.

last line is incorrect.

 

[eddy2017]

last line is incorrect.

where?. I am not seeing it.
[math](x+ 6)/2[/math][math]1/2x+3[/math]

 

[eddy2017]

Not quite. Check your math again.

[math]1/2x+3[/math]

 

[BigBeachBanana]

[math]1/2x+3[/math]

Correct, and you know how I got my answer. Now equate that to choices 1 and 3. Solve for x.

 

[Deleted member 4993]

where?. I am not seeing it.
[math](x+ 6)/2[/math][math]1/2x+3[/math]

(x + 6)/2 = ( x/2 ) + (6/2) = (x/2 ) + 3

 

[eddy2017]

(x + 6)/2 = ( x/2 ) + (6/2) = (x/2 ) + 3

Thanks.

 

[eddy2017]

Correct, and you know how I got my answer. Now equate that to choices 1 and 3. Solve for x.

Dr Khan has found that to be (x + 6)/2 = ( x/2 ) + (6/2) = (x/2 ) + 3
this is not the same as my result [math]1/2x+3[/math]

 

[Deleted member 4993]

where?. I am not seeing it.
[math](x+ 6)/2[/math][math]1/2x+3[/math]

In response 21 - the last line was

y = 2x + 3

That was the last line and that was incorrect.

 

[eddy2017]

In response 21 - the last line was

y = 2x + 3

That was the last line and that was incorrect.

Alright, the right result should have been like this.
[math]1/2x+ 3[/math]

 

[eddy2017]

following BBB I should equate this result to choices 1 and 3

so, choice 1 is [math]y=-x+3[/math]
[math]1/2x +3 = -x +3[/math]
Is that BBB what you mean by equating the equation in slope-intercept form with choice 1.

 

[Deleted member 4993]

1/2x+3=−x+3

Please stop and reflect - what information would you get out of that equation?

 

[eddy2017]

Please stop and reflect - what information would you get out of that equation?

I'll get back to you. Driving back home.

 

[eddy2017]

This is in answer to BBB's request to equate my equation in slope intercept form to choice 1 and 3 and solve for x
Choice 1
[math]1/2x+3=-x+3[/math][math]1/2x+3+x=-x+x+3[/math][math]3/2x+3=3[/math][math]3/2x+3-3=3-3[/math][math]3/2x=0[/math][math](2/3)(3/2x)=2/3(0)[/math][math]x=0[/math]
Now with choice 3
[math]1/2x+3=-2x+7[/math][math]1/2x+3+2x=-2x+2x+7[/math][math]5/2x+3=7[/math][math]5/2x+3-3=7-3[/math][math]5/2x=4[/math][math](2/5)(5/2x)=2/5(4)[/math][math]x=8/5[/math]
[math]x= 0[/math][math]x=8/5[/math]
Sorry for the delay. I can't access the site from my home computer since Saturday.
Gotta to work from my cell at home.

 

[Deleted member 4993]

x=0

x=8/5

What does these values of 'x' mean?

What was the purpose of calculating these?

 

[eddy2017]

What does these values of 'x' mean?

What was the purpose of calculating these?

The values if x is the value of the slope in both equations.
The purpose?
To prove that these two equations have a negative slope and hence a downward movement.