How do I solve these equations? (8x)^-3=64 8x^-3=64 Thanks! (:
A awsomelyy New member Joined Feb 7, 2010 Messages 1 Feb 7, 2010 #1 How do I solve these equations? (8x)^-3=64 8x^-3=64 Thanks!
J JuicyBurger Junior Member Joined Jan 26, 2010 Messages 96 Feb 7, 2010 #2 (8x)−3=1(8x)3=64\displaystyle (8x)^{-3} = \frac{1}{(8x)^3} = 64(8x)−3=(8x)31=64 Therefore... 164=(8x)3\displaystyle \frac{1}{64} = (8x)^3641=(8x)3 And I think you can get it from here? Hope this helps!
(8x)−3=1(8x)3=64\displaystyle (8x)^{-3} = \frac{1}{(8x)^3} = 64(8x)−3=(8x)31=64 Therefore... 164=(8x)3\displaystyle \frac{1}{64} = (8x)^3641=(8x)3 And I think you can get it from here? Hope this helps!
G garf Junior Member Joined Feb 5, 2010 Messages 74 Feb 7, 2010 #3 Hi awsomely! Do you realize the difference between both equations? Hint may be they don't have the same coefficient
Hi awsomely! Do you realize the difference between both equations? Hint may be they don't have the same coefficient
