Right Endpoint Integration Example - # 2

Jason76

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Find the Riemann sum for f(x)=4sinx\displaystyle f(x) = 4 \sin x, over interval [0,3π2]\displaystyle [0, \dfrac{3\pi}{2}] with six terms, taking the sample points to be right endpoints. (Round your answers to six decimal places.) Find R6\displaystyle R_{6} - the sixth right endpoint.

i=6nΔx[f(a+iΔx)]\displaystyle \sum\limits_{i=6}^n \Delta x [f(a + i \Delta x)]

Δx=ban\displaystyle \Delta x = \dfrac{b - a}{n}

Δx=3π206=π4\displaystyle \Delta x = \dfrac{\dfrac{3\pi}{2} - 0}{6} = \dfrac{\pi}{4}

n=6\displaystyle n = 6

i=6n(π4)[[f(0+(1)(π4)]+[f(0+(2)(π4)]+[f(0+(3)(π4)]+[f(0+(4)(π4)]+[f(0+(5)(π4)]+[f(0+(6)(π4)]]\displaystyle \sum\limits_{i=6}^n (\dfrac{\pi}{4}) [[f(0 +(1)(\dfrac{\pi}{4})] + [f(0 +(2)(\dfrac{\pi}{4})] + [f(0 +(3)(\dfrac{\pi}{4})] + [f(0 +(4)(\dfrac{\pi}{4})] + [f(0 + (5)(\dfrac{\pi}{4})] + [f(0 + ( 6)(\dfrac{\pi}{4})]]

i=6n(π4)[[f(0+(π4)]+[f(0+(2π4)]+[f(0+(3π4)]+[f(0+(4π4)]+[f(0+(5π4)]+[f(0+(6π4)]]\displaystyle \sum\limits_{i=6}^n (\dfrac{\pi}{4}) [[f(0 + (\dfrac{\pi}{4})] + [f(0 + (\dfrac{2\pi}{4})] + [f(0 + (\dfrac{3\pi}{4})] + [f(0 + (\dfrac{4\pi}{4})] + [f(0 + (\dfrac{5\pi}{4})] + [f(0 + (\dfrac{6\pi}{4})]]

i=6n(π4)[[f(0+(π4)]+[f(0+(π2)]+[f(0+(3π4)]+[f(0+π)]+[f(0+(5π4)]+[f(0+(3π2)]]\displaystyle \sum\limits_{i=6}^n (\dfrac{\pi}{4}) [[f(0 + (\dfrac{\pi}{4})] + [f(0 + (\dfrac{\pi}{2})] + [f(0 + (\dfrac{3\pi}{4})] + [f(0 + \pi)] + [f(0 + (\dfrac{5\pi}{4})] + [f(0 + (\dfrac{3\pi}{2})]]

i=6n(π4)[[f((π4)]+[f((π2)]+[f((3π4)]+[f(π)]+[f((5π4)]+[f((3π2)]]\displaystyle \sum\limits_{i=6}^n (\dfrac{\pi}{4}) [[f((\dfrac{\pi}{4})] + [f( (\dfrac{\pi}{2})] + [f( (\dfrac{3\pi}{4})] + [f( \pi)] + [f((\dfrac{5\pi}{4})] + [f((\dfrac{3\pi}{2})]]

i=6n(π4)[[4sin((π4)]+[4sin((π2)]+[4sin((3π4)]+[4sin(π)]+[4sin((5π4)]+[4sin((3π2)]]\displaystyle \sum\limits_{i=6}^n (\dfrac{\pi}{4}) [[4 \sin ((\dfrac{\pi}{4})] + [4 \sin ( (\dfrac{\pi}{2})] + [4 \sin ( (\dfrac{3\pi}{4})] + [4 \sin ( \pi)] + [4 \sin ((\dfrac{5\pi}{4})] + [4 \sin ((\dfrac{3\pi}{2})]]

i=6n(π4)[[4(.7071)]+[4(1)]+[4(.7071)]+[4(0)]+[4(.7071)]+[4(1)]]\displaystyle \sum\limits_{i=6}^n (\dfrac{\pi}{4}) [[4(.7071)] + [4(1)] + [4(.7071)] + [4 (0)] + [4 (-.7071)] + [4 (-1)]]

i=6n(π4)[[2.8284]+[4]+[2.8284]+[0]+[2.8284]+[4]]\displaystyle \sum\limits_{i=6}^n (\dfrac{\pi}{4}) [[2.8284] + [4] + [2.8284] + [0] + [-2.8284] + [-4]]

i=6n(.7854)[[2.8284]+[4]+[2.8284]+[0]+[2.8284]+[4]]\displaystyle \sum\limits_{i=6}^n (.7854) [[2.8284] + [4] + [2.8284] + [0] + [-2.8284] + [-4]]

i=6n[2.2214]+[3.1416]+[2.2214]+[0]+[2.2214]+[3.1416]\displaystyle \sum\limits_{i=6}^n [2.2214] + [3.1416] + [2.2214] + [0] + [-2.2214] + [-3.1416] - On the right track?
 
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