John, when this dawns on you, you'll slap yourself on the forehead real HARD!
Plus you'll realise why it's difficult to teach here, by typing...
John Whitaker said:
If you can see the 3 samples pka gave me, look at the first parenthetical term in the second sample... and the same in the third.
RE: The second: (-xy^2)^4 If the simplication of that is -x^3y^6, then the simplication of sample #3: (-xy^2)^4 should be (-x^4y^8). pka shows it to be: (x^4y^8). This is what I question. What happened to the minus sign in pka's third sample?
The second pka example is (-xy^2)^3, not (-xy^2)^4 : typo?
And simplification is -x^3y^6, same as -(x^3y^6)
Works same as if (-xy^2) was (-1): so (-1)^3 = -1, same as -(1)
-1 * -1 * -1 = -1
-xy^2 * -xy^2 * -xy^2 = -x^3y^6
The third pka example is (-xy^2)^4
And simplification is x^4y^8, NOT -x^4y^8
Works same as if (-xy^2) was (-1): so (-1)^4 = +1
-1 * -1 * -1 * -1 = +1
-xy^2 * -xy^2 * -xy^2 * -xy^2 = +x^4y^8
You also posted:
"Before pka threw in the towel, he wrote something that indicates even number exponents are treated differently than odd number exponents. I didn't understand the "n and j" parts, but... "
If an integer is even, then it is divisible by 2;
using n as integer means the integer is odd or even: can't tell, right?
so to ensure we're working with an even integer, we let n = 2j:
regardless of what j is, 2j is even; if j=3 : 2j=6=n.
Similarly, to ensure n is odd, we let n = 2j+1:
regardless of what j is, 2j+1 is odd; if j=3 : 2j=6+1=7=n.
Your "edited original" still has:
"Without LaTex, how do I express the Radical Sign?
My problem is: I have an open parenthesis... "3x"... then a Radical Sign with "4y" as a Radicand... close parenthesis... ^2 "
Without LaTex (which I'm too lazy to use!), use sqrt() for radical sign.
So your problem would be shown this way: (3x * sqrt(4y))^2
And that's same as (3x)^2 * (sqrt(4y))^2 = 9x^2 * 4y = 36x^2y: right?