Quickie on Simple problem, I'm confused ><
- Thread starter WTF?
- Start date
No, our diagrams are just shockingly out of scale!
Look at my modified picture:
The length from O to the middle of WZ is 2.5. Half the length of WX which was 5.
The length from the midpoint of WZ to that of BC is 1+1=2. This is from the width of the squares we were given.
So the length of the red dashed line is 2+2.5=4.5
The triangle ABC folds over BC to O, so its height is 4.5 also.
So, height of ABC = 4.5. Length of its base, BC, = 3.
The formula for the area of a triangle is
\(\displaystyle \L A = \frac{1}{2} bh\)
where \(\displaystyle b\) is the length of its base, and \(\displaystyle h\) is its height.
Is this making any sense?
Look at my modified picture:
The length from O to the middle of WZ is 2.5. Half the length of WX which was 5.
The length from the midpoint of WZ to that of BC is 1+1=2. This is from the width of the squares we were given.
So the length of the red dashed line is 2+2.5=4.5
The triangle ABC folds over BC to O, so its height is 4.5 also.
So, height of ABC = 4.5. Length of its base, BC, = 3.
The formula for the area of a triangle is
\(\displaystyle \L A = \frac{1}{2} bh\)
where \(\displaystyle b\) is the length of its base, and \(\displaystyle h\) is its height.
Is this making any sense?
Denis (to himself): "if the purpose of this problem is to show students
how to calculate the area of a triangle, then why oh why did the teacher
not simply state: triangle ABC has base BC = 3 and height from A to BC = 4.5;
what is ABC's area? " :idea:
how to calculate the area of a triangle, then why oh why did the teacher
not simply state: triangle ABC has base BC = 3 and height from A to BC = 4.5;
what is ABC's area? " :idea:
