ramizashraf
New member
- Joined
- Jul 7, 2006
- Messages
- 1
PLEASE SOLVE THIS f [ integration sign ] under root A square + under root X square dx
evaluate this . dx is not under the root. ok
[/code][/list]
please solve this integration
- Thread starter ramizashraf
- Start date
PLEASE SOLVE THIS f [ integration sign ] under root A square + under root X square dx
evaluate this . dx is not under the root. ok
[/code][/list]ChaoticLlama
Junior Member
- Joined
- Dec 11, 2004
- Messages
- 199
Just to clarify, if this the question you stated?
\(\displaystyle \L\int {\frac{{dx}}{{\sqrt {a^2 + x^2 } }}}\)
please learn latex or type more precisely.
if that is indeed the problem, then you should know to use the substitution:
let \(\displaystyle x = a\tan \theta\)
\(\displaystyle \L\int {\frac{{dx}}{{\sqrt {a^2 + x^2 } }}}\)
please learn latex or type more precisely.
if that is indeed the problem, then you should know to use the substitution:
let \(\displaystyle x = a\tan \theta\)
Hello, ramizashraf!
I don't think you meant what you wrote . . .
You wrote:
\(\displaystyle \text{[ integration sign ] }\underbrace{under\,root\,A\,square} \,+\,\underbrace{\text{under root }x\,square}\; dx\)
. . . . . . . . . . . . . . . . . . . . . . . . . . \(\displaystyle \sqrt{A^2}\) . . . . . . . . . . . . . . . . .\(\displaystyle \sqrt{x^2}\)
And this is just: \(\displaystyle \,\int(A\,+\,x)\,dx\) . . . not very challenging!
I don't think you meant what you wrote . . .
You wrote:
\(\displaystyle \text{[ integration sign ] }\underbrace{under\,root\,A\,square} \,+\,\underbrace{\text{under root }x\,square}\; dx\)
. . . . . . . . . . . . . . . . . . . . . . . . . . \(\displaystyle \sqrt{A^2}\) . . . . . . . . . . . . . . . . .\(\displaystyle \sqrt{x^2}\)
And this is just: \(\displaystyle \,\int(A\,+\,x)\,dx\) . . . not very challenging!