pigs in a pan

[reggaetony]

There are 27 pigs and 4 pens.
An odd number of pigs in each of 4 pens for a total of 27 pigs.
Nat also claims that if Gio took apart his largest pen he will still have the same number of penned pigs.

 

[mmm4444bot]

We need to see the entire exercise.

Please read the post titled, "Read Before Posting."

Cheers

 

[BigGlenntheHeavy]

$\displaystyle Let \ 2a-1 \ = \ odd \ number \ of \ pigs, \ 2b-1,2c-1, \ and \ 2d-1, \ ditto. a,b,c,d \ positive \ integers.$

$\displaystyle Then \ (2a-1)+(2b-1)+(2c-1)+(2d-1) \ = \ 27$

$\displaystyle \implies \ 2a+2b+2c+2d \ = \ 31 \ \implies \ 2(a+b+c+d) \ = \ 31$

$\displaystyle Let \ x \ =a+b+c+d, \ all \ integers, \ then \ 2x \ = \ 31, \ but \ 2x \ is \ an \ even \ integer, \ hence \ impossible,$

$\displaystyle ergo \ trick \ problem, \ as \ there \ is \ no \ way \ you \ can \ divide \ 27 \ pigs \ into \ 4 \ pens \ and \ have \ an \ odd$

$\displaystyle number \ of \ pigs \ in \ each \ pen.$

 

[Denis]

Sure you can, BigG: 3 pens are inside a large pen (trick-like question).

 

[BigGlenntheHeavy]

Denis, is this what you meant? I assume that each pen was separate. Note: If you dismantle the larger pen

then you will have the correct answer, but this is a poor joke. I'm going to bed, I had it.

[attachment=0:1pdfkuuo]asa.JPG[/attachment:1pdfkuuo]

 

[Denis]

Ya BigG: you are finally "learning" :lol: