eddy2017
Elite Member
- Joined
- Oct 27, 2017
- Messages
- 2,525
this is what i did in my first post.Wow Eddy. I recognize that this has already been implied, but let me stress it.
What the Khan of Khans calls the find, I call unknowns. What numbers we not know? TWO NUMBERS : Chris's share and Kelly's shares. Therefore we need two variable names. Not x and the "other x" as you said in your first post. That is missing a critical element of algebra: each unknown is given its own distinct name. Let's use c and k.
Always note exactly but concisely what those names mean.
In your first post, what in the world does x represent? You have not told us. It is a major reason for your problem.
c = what chris gets.
k = what kelly gets.
Do this before you start working on equations. This is part of a systematic way to work on every word problem in algebra.
If you have n unknowns, you need n equations for a numeric solution. Here we have two unknowns so we need two equations.
One is c + k = 400.
What is the other?
The only thing I am thinking right now is to set up two equations with two variables.
5x+ 3x= 400
8x=400
x=50
Replacing the other x with its value.
3(50)=150
So I have two values now
50
And 150
but did not what to do with the two values for x. can you explain following this same reasoning, whaty would you do next?
It was right here that I got stuck. I'm home now at my desktop.