this is the question
Suppose that a car can accelerate from 30 mph to 50 mph in 4 seconds. Assuming a constant acceleration, find the acceleration (in miles per second squared) of the car and find the distance traveled by the car during the 4 seconds.
the
FIND of the problem is "distance" traveled.
Given of the problem is:
Initial velocity = 30 mph = u
final velocity = 50 mph = v
elapsed time = 4 sec = 1/900 hour = t
Assume linear motion and constant acceleration - then we can use Galileo's equations (a = acceleration and s = distance traveled)- which are:
v = u + a*t............................(1)
s = u*t + (1/2) * a * t^2.........(2)
v^2 = u^2 + 2 * a * s ...........(3)
Looking at these equations (and other givens) - we formulate our strategy:
using equation (1) we get,
a = (v - u)/t = 18000 mph^2 ....................(be very cognizant about the
units in these problems)
then we use equation (3), to get,
s = (v^2 - u^2)/(2*a) ................................complete it using the given and the calculated data. Be careful about the
unit of 's'.
and the FIND is found!