logistic_guy
Full Member
- Joined
- Apr 17, 2024
- Messages
- 674
i really appreciate your standing with me so far blamocur
\(\displaystyle \sigma_2 + \sigma_3 + \sigma_5 = (a - b\sqrt{2} - c\sqrt{3} - d\sqrt{5})\) + \(\displaystyle (a + b\sqrt{2} + c\sqrt{3} - d\sqrt{5})\) + \(\displaystyle (a - b\sqrt{2} - c\sqrt{3} + d\sqrt{5})\) = \(\displaystyle a + a + a - b\sqrt{2} - c\sqrt{3} - d\sqrt{5}\) = \(\displaystyle \sigma_2\)
there is \(\displaystyle 8\) automorphisims in the list. i don't understand why do you chose only \(\displaystyle \sigma_3,\sigma_4,\sigma_6\). i don't see how these used to get others!
\(\displaystyle \sigma_2 + \sigma_3 + \sigma_5 = (a - b\sqrt{2} - c\sqrt{3} - d\sqrt{5})\) + \(\displaystyle (a + b\sqrt{2} + c\sqrt{3} - d\sqrt{5})\) + \(\displaystyle (a - b\sqrt{2} - c\sqrt{3} + d\sqrt{5})\) = \(\displaystyle a + a + a - b\sqrt{2} - c\sqrt{3} - d\sqrt{5}\) = \(\displaystyle \sigma_2\)
there is \(\displaystyle 8\) automorphisims in the list. i don't understand why do you chose only \(\displaystyle \sigma_3,\sigma_4,\sigma_6\). i don't see how these used to get others!