Jakeboulter
New member
- Joined
- Feb 18, 2020
- Messages
- 23
Thank you for your help, no one is telling me that the method used to get to 0 is wrong. I just want to be sure before submitting my answer. I'm using an online course and I'm not getting any feedback to the questions I'm asking. Thanks again for your help I think I'll go with the 0.You forgot that u is in radians, not degrees! You can't subtract 360's from it; if anything, it would be 2pi's.
But if you just evaluate the cosine of 1583.362697..., you'll find that it is 1. (Even with your rounded value, you'll get 0.9999999996.)
Using a different (valid) method to evaluate an integral can't change the answer! It is still 0.
If someone or something is telling you that 0 is the wrong answer, then you'll have to ask why. The best bet is that they mean something other than the literal mean (perhaps the mean absolute voltage). But taking the question at face value, the answer is 0.
I think in this problem, the "implied" unit of 't' is seconds. Thus, the limits of integration should be 0 to 0.0036. In that case the "mean" will not be 0.Thank you for your help, no one is telling me that the method used to get to 0 is wrong. I just want to be sure before submitting my answer. I'm using an online course and I'm not getting any feedback to the questions I'm asking. Thanks again for your help I think I'll go with the 0.
Thanks I'll work it out again with that in mind.I think in this problem, the "implied" unit of 't' is seconds. Thus, the limits of integration should be 0 to 0.0036. In that case the "mean" will not be 0.
Why did you divide by 3.6 when T = 0.0036 secLast ditch attempt I'm hoping this is the one.
Thanks for pointing that out I just spotted it as I was scanning it in to the computer.Why did you divide by 3.6 when T = 0.0036 sec
Would it be right then that the mean would be greater than the total?Why did you divide by 3.6 when T = 0.0036 sec
Sorry by total I ment total voltage but was looking at the wrong bit I've attempted this a different way so many times its thrown me. It's the last question in the unit I need to get right. My new mean now is 140.6899...What do you mean by "total"? My concern would be whether the mean is greater than the maximum, 220. (It isn't.)
Another check would be to compare 0.0036 with the period, to get a sense of how large to expect the mean to be, graphically. What you'll find is that it's about a quarter cycle, which might give you an idea of the result to expect.
(I apologize for not having noticed the unit issue. In your context, seconds is probably an assumed default, but in math it would be an error on their part not to define the variable as measured in seconds, which would have clarified the problem.)
So that ended up being wrong aswell. I've not been given the answer so not sure what it could be. I'll just have to live with a Merit rather than distinction for that unit.That's what I get, and it makes sense because it is a significant fraction of 220.
You may possibly have seen that the mean absolute value of a sinusoid is 2/pi = 0.64 times the peak; and that's just what 140 is in this case, because we're averaging over a quarter cycle.