Like this, right?.Unless you want to know which of two fractions is larger or equal I think that you should NEVER cross multiply, especially if you are going to do it wrong.
You have 0.5 / 40 mi = x in / 280 mi. Just multiply both sides by 280 miles.
Thanks.The objective being isolating the variable x.
The objective being isolating the variable x.
Have you solved for x?Like this, right?.
`280 (0.5/40mi)= 280 (x / 280mi)`
It is the same thing but easier.Have you solved for x?
Nope, sorry. [math]280(\dfrac{x}{280}miles) \neq x.[/math]It is the same thing but easier.
The 280's cancel out on the right hand side and then solve for x is easy. X is by itself.
I was only writing it out cos I like your proposal.
I am in doubt.Nope, sorry. [math]280(\dfrac{x}{280}miles) \neq x.[/math]
Maybe I am being a bit hard but that right hand side does not equal x. Tell me why? What do you need to do so the hrs is x
There was more than 280x/280I am in doubt.
If the 280's do not cancel out, what happens then?.
The other possibility that I see is:
280x/280
Good morning. I though you decided to multiply both sides by 280 as a very easy way to leave x by itself on the right side. I don't see any other thing there.There was more than 280x/280
There was a "syntactic" problem with your statement - NOT a "numerical" one.I am in doubt.
If the 280's do not cancel out, what happens then?.
The other possibility that I see is:
280x/280
Put in the units and finish up.
[math]x= \dfrac{.5 in * 280 miles}{40 miles} = 3.5 in[/math]
Like here. This is good. You said it was good.Okay. Thanks.
`0.5/(40mi)= (x mi)/(280 mi)`
Ok, let me give a try at solving this the correct way.Like here. This is good. You said it was good.
I'm just having trouble understanding the thing about the dangling mile here.
?\frac{0.5}{40mi}=\frac{xmi}{280mi}
That was a mistake when writing. Give me a little bit of time to solve it
`05 in = xLike here. This is good. You said it was good.
I'm just having trouble understanding the thing about the dangling mile here.