Complicated Limit Problems

[jonah2.0]

Beer soaked ramblings follow.

Just from the image of the exercise you put in the first post in this thread.

That must have been an exhausting search.
I was almost sure you've seen his posts where he kept mentioning the author's name.

 

[lex]

Beer soaked ramblings follow.

That must have been an exhausting search.
I was almost sure you've seen his posts where he kept mentioning the author's name.

That would have been too easy!

 

[nycmathdad]

Just from the image of the exercise you put in the first post in this thread.

Brother, if you are going to help me with my threads by providing hints and insight, terrific. If you are simply looking to leave a comment here and there without leading to math help, then please move on. Nothing personal, of course.

 

[lookagain]

Brother, ...

nycmathdad, in post # 15 and highlighted above in post # 23, you addressed
a member incorrectly. They are not "brother" to you. You are to use their
username in addressing them or just not address them.

 

[nycmathdad]

nycmathdad, in post # 15 and highlighted above in post # 23, you addressed
a member incorrectly. They are not "brother" to you. You are to use their
username in addressing them or just not address them.

And???

 

[lookagain]

And???

nycmathdad, no, that response from you does not make sense.
If anything, something along the lines of this one would:

I understand.

Else, you are adding to a history of uncivil/argumentative/demanding
messages in posts that counter to the forum rules.

 

[lex]

Just from the image of the exercise you put in the first post in this thread.

Brother, if you are going to help me with my threads by providing hints and insight, terrific. If you are simply looking to leave a comment here and there without leading to math help, then please move on. Nothing personal, of course.

@nycmathdad
This comment was a reply to a question you asked me twice - in post #16 and post #20. I hoped that post #5 would have been helpful to you in completing your questions.
Goodbye and good luck with your mathematical studies.

 

[Deleted member 4993]

View attachment 25766

Expanding on suggestions by DrP (response #4), use:

(p + q) * (p - q) = p² - q²

 

[nycmathdad]

@nycmathdad
This comment was a reply to a question you asked me twice - in post #16 and post #20. I hoped that post #5 would have been helpful to you in completing your questions.
Goodbye and good luck with your mathematical studies.

Thanks, brother.

 

[nycmathdad]

@nycmathdad
This comment was a reply to a question you asked me twice - in post #16 and post #20. I hoped that post #5 would have been helpful to you in completing your questions.
Goodbye and good luck with your mathematical studies.

THANKS, BROTHER.