Completing the Square x^2 + 12x + 32=0

[lookagain]

Step 6

We need to take the square of both sides, so,

√(x+6)^2= √4

x+6= ±2

eddy2017, you are taking the square root of both sides.

√(x+6)^2 = √4 $\displaystyle \ \ \ \ \ \ \$ <----- This is a correct step. It is equivalent to:

|x + 6| = 2 $\displaystyle \ \ \ \ \ \ \ \$ <----- That leads to:

x + 6 = ±2 $\displaystyle \ \ \ \ \ \ \$ <----- That can be read as "x plus 6 equals positive or negative 2."

x = -6 ± 2 $\displaystyle \ \ \ \ \ \ \ \$ <----- That can be read as "x equals negative 6 plus or minus 2."

x = -6 - 2 $\displaystyle \ \$ or $\displaystyle \ \$ x = -6 + 2

x = -8 $\displaystyle \ \$ or $\displaystyle \ \$ x = -4

 

[eddy2017]

Oh thanks a lot. You really made lookagain. You put it in clear perspective for me. Thank you.