basic infinite series

[topsquark]

thank steven very much for aiming to say i'm the weakest student


i'm back

i see the graph of the lograthm

View attachment 38966

i see it touch zero and go right
how this help me?

What does the ln function tend to as x tends to infinity? It's a limit!! Pre-Calc. Limits!

-Dan

 

[logistic_guy]

What does the ln function tend to as x tends to infinity? It's a limit!! Pre-Calc. Limits!

-Dan

i think i get idea of the limit from the other thread

\(\displaystyle \lim_{M \to \infty} \ln M = \infty\)

am i correct?

 

[topsquark]

i think i get idea of the limit from the other thread

\(\displaystyle \lim_{M \to \infty} \ln M = \infty\)

am i correct?

Finally!

-Dan

 

[logistic_guy]

Finally!

-Dan

it seem i'm mastering the subject. i can't believe it

 

[khansaheb]

it seem i'm mastering the subject. i can't believe it

What is the "proper" answer to the query posted in post #1 ?

 

[topsquark]

it seem i'm mastering the subject. i can't believe it

I would hardly call this "mastery." First, this took you way too long to get, and this is a simple problem.

-Dan

 

[logistic_guy]

What is the "proper" answer to the query posted in post #1 ?

we know
\(\displaystyle \int_{1}^{\infty} \frac{1}{x} dx \leq \sum_{n=1}^{\infty}\frac{1}{n}\)
we show \(\displaystyle \int_{1}^{\infty} \frac{1}{x} dx\) diverg
then by comparison test \(\displaystyle \sum_{n=1}^{\infty}\frac{1}{n}\) diverge too

I would hardly call this "mastery." First, this took you way too long to get, and this is a simple problem.

-Dan

it take a long time to solve a specific question at the first time
it take no time to solve question with the same concept second time

it's a rule of thumb if you know it

 

[topsquark]

it take a long time to solve a specific question at the first time
it take no time to solve question with the same concept second time

it's a rule of thumb if you know it

Learning it the second time around is easier. But forgive me for saying that if it were that easy for you, you'd've remembered it from Calc I. You seem to be trying to learn how to solve specific problems rather than learning the concepts, so I doubt that you've mastered this so quickly.

-Dan

 

[logistic_guy]

Learning it the second time around is easier. But forgive me for saying that if it were that easy for you, you'd've remembered it from Calc I. You seem to be trying to learn how to solve specific problems rather than learning the concepts, so I doubt that you've mastered this so quickly.

-Dan

i appreciate your presence and advice in all of my threads. they help me

thank very much

 

[Steven G]

thank steven very much for aiming to say i'm the weakest student

When did I say that you're the weakest student?

 

[logistic_guy]

When did I say that you're the weakest student?

your post number \(\displaystyle 19\) imply that

 

[Steven G]

your post number \(\displaystyle 19\) imply that

My reply just said that someone who is bad at calculus, not necessarily you, can still "pass" the course. Whether or not you are in that situation I do not know.

 

[logistic_guy]

My reply just said that someone who is bad at calculus, not necessarily you, can still "pass" the course. Whether or not you are in that situation I do not know.

yeah i'm bad at calculus and i pass the course, but i'm not the weakest student