skeeter
Elite Member
- Joined
- Dec 15, 2005
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distributive property of multiplication ...One thing though why you raised -2w to the Power of 2?
[imath]A = LW = (48-2W)W = 48W-2W^2[/imath]
distributive property of multiplication ...One thing though why you raised -2w to the Power of 2?
We have explained the Distributive Property to you multiple times over the past few years, Eddy. Something is wrong.I see it now
That statement seems to be the opposite of what you'd posted.I was confused by the way skeeter set his work up
Years?it takes a while for something to register
What difference does that make, when it comes to study habits?I am studying on my own
Yet, something is not right. You post an exercise. After much struggling, you declare that you "get it". Several months later, you post the same exercise, and you can't even begin. If you don't view that as an issue, then so be it.you all will be hard pressed to find a student so immersed into the subject as me and someone who devotes his entire free time to do this.
Are you working with pen and paper?One thing though why you raised -2w to the Power of 2?
Can you write that out and post it as a mathematical expression?raised -2w to the Power of 2?
Don’t worry about it. He is applying calculus, which is one way to solve this problem, but not necessary here because it can be solved by algebra alone.A Hispanic teacher explained another way to say this, but for the life of me i did not make head or tail of it. i am bringing it here just as he explained it to see if you can help me decipher all this and understand the why of some things he explained. This is a totally different way that skeeter used, which for me it was way more clear.
my rough translation of what he said and did:
Well, here it is:
The area measure S of the rectangle is xy. S is a function of two variables. S(x;y)=xy
We know the equation 2x+y=48
We can therefore calculate y as a function of x.
y=48-2x
so S is a function of the single variable x.
Once S(x) is calculated, we look for its maximum. Either by calculating the derivative S' and drawing up the table of variations of S, or, S being a second degree trinomial of the variable x, by returning to its canonical form.
The maximum area is 288 SINCE x=12 and y=24
I don't understand what he did.
He also shows an algebraic method, Jeff, where he manipulates the quadratic equation into vertex form (revealing the parabola's maximum y-coordinate, as you know).He is applying calculus, which is one way to solve this problem