Cant solve volume integration problem: Sin(x) between 0 and pi, abt x = -1, by shells

[dchiuda]

Sin(x) between 0 and pi. Find the volume of the solid by revolving this region about the line x = −1 using the methodof cylindrical shells.

i get the height to be h=sin(x) and radius to be r=x+1

When I integrate for volume Integral from 0-pi for (2)(pi)(x+1)(Sin(x)) I get a negative value.

Please help I have been trying this problem for such a long time and need to move onto other classes

 

[Deleted member 4993]

Sin(x) between 0 and pi. Find the volume of the solid by revolving this region about the line x = −1 using the methodof cylindrical shells.

i get the height to be h=sin(x) and radius to be r=x+1

When I integrate for volume Integral from 0-pi for (2)(pi)(x+1)(Sin(x)) I get a negative value.

Please help I have been trying this problem for such a long time and need to move onto other classes

When I integrate, I get a positive value.

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