Suppose that a function f satisfies the following conditions for all real values of x and y.
a: f(x+y)=f(x)*f(y)
b: f(x)=1+xg(x), where the limit x(approaches 0) g(x)=1.
Show f '(x)= f(x).
Can someone show how to do this in steps, specifically the derivative part?
a: f(x+y)=f(x)*f(y)
b: f(x)=1+xg(x), where the limit x(approaches 0) g(x)=1.
Show f '(x)= f(x).
Can someone show how to do this in steps, specifically the derivative part?