Intermediate/Advanced Algebra

For more advanced algebra topics, including Algebra II and Pre-Calculus.
J
Looking for clarification on this equation: solve y=-12.34ln(x)+133.72 for x
Replies
7
Views
1K
pka
pka
J
How to solve logarithmic problem: log k(k/a^3)= log k a= 10, log k b = -0.4, log k c
Replies
1
Views
673
Dr.Peterson
Dr.Peterson
S
Arithmetic sequence: We throw an object from the hight of 12,261 meters.
Replies
8
Views
1K
Stripey
S
L
Cannot sort: Given that f(x) = 3x+1 and g(x) = x^2 solve fg(x) = gf(x)
Replies
3
Views
822
Deleted member 4993
D
M
Solving 4x3 Matrix: [[1 2 3][2 -1 1][0 1 1][1 -1 0]]*[[x][y][z]]=[[-3][4][-2][a]]
Replies
8
Views
5K
Mrmatheco
M
A
am I right here?
Replies
4
Views
875
Dr.Peterson
Dr.Peterson
V
I need help with log
Replies
4
Views
909
sinx
S
G
Polynominal inequality: (x + 7) (x + 1) >= 0
Replies
8
Views
1K
Dr.Peterson
Dr.Peterson
A
logn(x)/logn(y) = logy(x) ~ Is this a thing?
Replies
7
Views
1K
anonybystander
A
shahar
logarithm: 1/4 >1/8 leads (by logs) to 2 > 3; what is going wrong here?
Replies
6
Views
1K
JeffM
J
G
System of 3 eqns: y^2+y*x-z-x = 0, z^2+z*y-x-y = 0, x^2+x*z-y-z = 0
Replies
2
Views
558
Gosia
G
S
Prove 1/(4n+1)<[1*3*5*...*(2n-1)]^2 / [2*4*6*...*2n]^2 <1/(3n+1)
Replies
5
Views
1K
lookagain
L
I
Logarithm & Surds: rect. has length of (5+√3) cm, area of (5 + 2√3) cm^2
Replies
5
Views
1K
HallsofIvy
H
shahar
Ordered Numbers: complexes aren’t; are any others not? are infinitesimals ?
Replies
2
Views
910
topsquark
topsquark
P
Stuck! “Find b so 0=-x2 + bx -8 has one solution.”
Replies
3
Views
968
Denis
D
N
Complex numbers: show that (2+j)e^(1+j3)x + (2-j)e^(1-j3)x is also real
Replies
3
Views
1K
Dr.Peterson
Dr.Peterson
J
One-to-One Functions; g & h defined.
Replies
3
Views
741
JeffM
J
K
Limits: Does (1 - 1/4)(1 - 1/9) ... (1 - 1/n^2) converge as n approaches zero?
Replies
6
Views
884
lookagain
L
W
Discrete Dynamical Systems (interaction of two species)
Replies
0
Views
600
Wothom83
W
P
Positive Definite Matrix: H_p is minor obliterating n-p rows and...
Replies
0
Views
650
Poliwrath
P
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