zeros of quadratic function are (4 + 3i) and (4 - 3i)

[kingrotty]

The zeros of a quadratic function are given by (4 + 3i) and (4 - 3i). Write the quadratic function in standard form.

This is the answer I got. F(x)= (x - 4)^2 + 9
I believe that thats the standard form.
These are my steps
(x - 4 +3i)(x - 4 + 3i)
all mutiplied out
= x^2 -8x +25
I complete the square
= (x^2 - 8x + 16)-16 +25
= (x - 4)^2 + 9

Is this correct ? Thanks for any help in advance

 

[Deleted member 4993]

Re: Algebra problem

The zeros of a quadratic function are given by (4 + 3i) and (4 - 3i). Write the quadratic function in standard form.

This is the answer I got. F(x)= (x - 4)^2 + 9
I believe that thats the standard form.
These are my steps
(x - 4 +3i)(x - 4 - 3i) <<< This could be A * (x-4+3i)(x-4-3i) .... "A" being a constant
all mutiplied out
= x^2 -8x +25
I complete the square
= (x^2 - 8x + 16)-16 +25
= (x - 4)^2 + 9

Is this correct ? Thanks for any help in advance

Looks good except as noted above.

 

[kingrotty]

Re: Algebra problem

Ok, but would my answer be correct or should I add the a in and then would that change my answer.