You are enclosing a garden with prefabricated fencing....

Jeff24

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Mar 1, 2009
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You are enclosing a garden with prefabricated fencing you salvaged froma lanfill. YOu found 18 pices of fence taht are each 5 feet long. What is the maximum rectangular area you can enclose with these pices of fence?

How ould i set it up?

would i use A=L times W
oR permitter P=2(l+W) ?
 
Re: Story Problem

What grade are you in?

You have a total of 90 feet, right?
I guess we assume you can't "cut" a 5 feet section.
A square produces largest area : did you know that?

But we can't have a square here: no cutting!
So best you can do is a rectangle closest possible to a square, hence 25 by 20.
That's area of 25*20 = 500

If you could cut and form a square: 22.5 by 22.5 = 506.25 ; larger area, right?
If that mixed you up, see your teacher: I don't know what level you're at.
 
Re: Story Problem

I'm a sophmore so i think this realtes ot it it's a geometry question
 
Re: Story Problem

so i think were just supposed to find area so than the answer would 500?
 
Re: Story Problem

Jeff, QUIT using 2 names... :shock:
 
Re: Story Problem

I got a new one because I forgot my old one but then i would remembered my old one sry, so i think the answer would jsut be 500 does that make sense?
 
Re: Story Problem

MathIQ said:
I got a new one because I forgot my old one but then i would remembered my old one sry, so i think the answer would jsut be 500 does that make sense?
You get no answer from me until you SLOW DOWN and re-type the above in PROPER English.
 
Re: Story Problem

Sorry, I'm unsure If this is correct or not because I'm only in geometry so I don't think were that advanced yet.
It sasy that We are enclosing a garden with prefabricated fencing you salvaged from a landfill. YOu found 18 pieces of fence that are each 5 feet long. What is the maximum rectangular area you can enclose with these pieces of fence?

1. So what I think we would have to do is take A=L * W
2. So that would be A=90 feet, but then how would we find the masimum rectangular area?
3. Or is that all we would have to do would be get A=90 feet?
Thanks
 
Re: Story Problem

Also If you could help me with another problem right below this one, on the chart thing. It would be appreciated!
I have x solved but am just wondering if there's anything more I do for that problem.
 
Jeff, there is no area anywhere in the universe that measures 90 feet.

You were given eighteen 5-foot lengths. You multiplied 18 times 5 to get 90, and then you decided that 90 is the area of the rectangle.

Clearly, you forgot the definition of area.

You need intense tutoring.

We cannot continue to provide intense tutoring for you, over the Internet. (Well, at least, I cannot.)

Please speak with your instructor about getting a qualified tutor who can spend a lot of time with you face-to-face.

If your instructor has no help to offer, then ask their boss. If the boss has no help to offer, as well, then tell me the name of your school and the city and state in which it's located. (If you're outside of the USA, then you're on your own.)

 
MathIQ said:
Also If you could help me with another problem right below this one, on the chart thing. It would be appreciated!


We call the "chart thing" a message-board index. (Look at the top of the chart thing. Do you see the words "Board Index"?)

Why are you even telling us that you have other posts at this web site? Are we not responding to your posts quickly enough? (Perhaps, it's the same reason for why you continue to start duplicate threads for the same exercises.)

Everyone can see what you're doing; you do not need to waste your time posting messages meant to guide us to other posts.
 
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