yo can somebody get me started on this prob

[jas397]

[1-(sin^2(x))(cos^2(x))/cos^ 4(x)=tan^4(x)+tan^2(x)+1

:?

 

[galactus]

I'll get you started, then you finish. OK?.

You have:

$\displaystyle \frac{1-sin^{2}xcos^{2}x}{cos^{4}x}$

=$\displaystyle \frac{1}{cos^{4}x}-\frac{sin^{2}xcos^{2}x}{cos^{4}x}$

=$\displaystyle \frac{1}{cos^{4}x}-\frac{sin^{2}x}{cos^{2}x}$

Now, use the identities $\displaystyle \frac{sinx}{cosx}=tanx$ and $\displaystyle tan^{2}x+1=\frac{1}{cos^{2}x}$ to finish.

 

[stapel]

Yo: what have YOU tried?

[1-(sin^2(x))(cos^2(x))/cos^ 4(x)=tan^4(x)+tan^2(x)+1

You have an unmatched bracket at the beginning of your character string. Did galactus guess your meaning correctly?

Please confirm or correct. When you reply, please show what you have done. Thank you.

Eliz.