yo can somebody get me started on this prob
- Thread starter jas397
- Start date
I'll get you started, then you finish. OK?.
You have:
\(\displaystyle \frac{1-sin^{2}xcos^{2}x}{cos^{4}x}\)
=\(\displaystyle \frac{1}{cos^{4}x}-\frac{sin^{2}xcos^{2}x}{cos^{4}x}\)
=\(\displaystyle \frac{1}{cos^{4}x}-\frac{sin^{2}x}{cos^{2}x}\)
Now, use the identities \(\displaystyle \frac{sinx}{cosx}=tanx\) and \(\displaystyle tan^{2}x+1=\frac{1}{cos^{2}x}\) to finish.
You have:
\(\displaystyle \frac{1-sin^{2}xcos^{2}x}{cos^{4}x}\)
=\(\displaystyle \frac{1}{cos^{4}x}-\frac{sin^{2}xcos^{2}x}{cos^{4}x}\)
=\(\displaystyle \frac{1}{cos^{4}x}-\frac{sin^{2}x}{cos^{2}x}\)
Now, use the identities \(\displaystyle \frac{sinx}{cosx}=tanx\) and \(\displaystyle tan^{2}x+1=\frac{1}{cos^{2}x}\) to finish.
- Joined
- Feb 4, 2004
- Messages
- 16,582
Yo: what have YOU tried?
Please confirm or correct. When you reply, please show what you have done. Thank you.
Eliz.
You have an unmatched bracket at the beginning of your character string. Did galactus guess your meaning correctly?jas397 said:
Please confirm or correct. When you reply, please show what you have done. Thank you.
Eliz.