y = x^(1/3) defined from negative infinity to zero?

[Idealistic]

Is y = x^(1/3) defined from negative infinity to zero? I don't see why not, none of it's x values have more than one corresponding y value, it has no crazy jumps in continuity, but when I graph it online its only defined from zero to infinity.

 

[Deleted member 4993]

Is y = x^(1/3) defined from negative infinity to zero? I don't see why not, none of it's x values have more than one corresponding y value, it has no crazy jumps in continuity, but when I graph it online its only defined from zero to infinity.

That's the problem with computer graphing - the cheap ones.

(1/3) is approximated as (0.33333333) and then 3*0.333333333 = 0.99999999 is not equal to one. Thus the negetive number roots (non-integer) goes to complex numbers.