y=l5l-(1)^2: does the bar mean 'such that'?

[Kathleen bell]

I'm kind of confused by this problem because my teacher just introduced us to the "such that" terminology. Isn't that what the lines around 5 are? Could comeone please help me with the problem:

y=l5l-(1)^2

I know that 1^2 is just one, but I can't grasp what the "such that" means in the middle fo a problem. It made more sense when it was in a definition.

 

[galactus]

From all I've seen, that's absolute value, not 'such that'.

 

[stapel]

A vertical line in the middle of a set definition can be "such that". For instance: A = {x | x = sqrt[n] for some natural number n} is read as "the set A is the set of all x 'such that' x equals the square root of some natural number n".

But in an equation, the vertical line does not mean this. (Context is important.) In an equation, the double vertical line is the absolute-value notation you've seen and studied before.

Meanwhile, you have included no instructions for your equation, "y = |5| - 1²", which simplifies as "y = 4". What are you supposed to do with this?

Thank you.

Eliz.