y"-[1-(y')^2]y'+y=0 qualitative analysis

Integrate

Junior Member
Joined
May 17, 2018
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Okay so I rewrite it as


[math]y'' + [(y')^2 - 1]y' + y = 0[/math]

So if I understand right damping is energy lost from the oscillation.


So if there is no damping there will be an infinite oscillation.


With that thinking a negative damping will cause an increasing amplitude of the sinusoid.

1.) When y'=-1,1 we get infinite oscillation.
2.) When -1 < y' < 1 we get negative damping and therefor increasing amplitude.
3.) When -1 > y' > 1 we get positive damping and therefor decreasing amplitude.



However, I just cannot understand how that relates to these graphs of this DE.


Rayleigh.png
 
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