(x-a)(x-b). . . . (x-z): should I be using binomial theorem?

[roadrunner]

(x-a)(x-b). . . . (x-z)

Should I be using the binomial theorem for this? I am very confused.

 

[Deleted member 4993]

Re: (x-a)(x-b). . . . (x-z)

Should I be using the binomial theorem for this? I am very confused.

Write out the problem - all the way instead of "...". You'll - should - see something interesting. No mathematical operation needed.

 

[stapel]

(x-a)(x-b). . . . (x-z)

I will guess that the instructions were something along the lines of "simplify" or "evaluate". As suggested earlier, further expansion would be very helpful (because this is, in a sense, sort of a "trick" question).

Hint: Start expanding from the back end: (x - z)(x - y).... and so forth. :wink:

Eliz.

 

[roadrunner]

Yes, I did do some further expansion but have had to stop and have a long drive. I'll try to get back to it tonight. I do see a pattern and have started to write it out. I am reviewing this material with another student, trying to help him!

 

[Deleted member 4993]

Before you take up any huge mathematical operation, remember what Stapel told you -
It is a trick question!!!

 

[roadrunner]

Yes, I had a long drive home and realized that the answer is obviously zero.

Good grief. Stress can really affect my thinking process.

Thanks for your patience!