(x-5)(x-s)=x^2-rx+10, find r+s

[onedirect]

The school year just started and I can't figure out how to solve this.

If (x-5)(x-s)=x^2-rx+10, what is the value of r+s?

I can't seem to figure out how to isolate r+s.. I've foiled the left side, and I've tried moving things around but I'm flustered. Help?

 

[Lost souls]

The school year just started and I can't figure out how to solve this.

If (x-5)(x-s)=x^2-rx+10, what is the value of r+s?

I can't seem to figure out how to isolate r+s.. I've foiled the left side, and I've tried moving things around but I'm flustered. Help?

your equation can be written as
x²-(5+s)x+5s= x²-rx+10
equating terms with same power of x,
5+s = r
and 5s=10 =>s=2;
hence r=5+2;
r=7

r+s= 2+7=9