stellardrone
New member
- Joined
- Sep 22, 2020
- Messages
- 5
Hello! This is my first post, I hope this is in the right sub-section/topic. Currently working through an Algebra book (Introduction):
I have difficulties with a double fraction.
[MATH] \frac{2x^{-3}}{x^{5}} [/MATH] should be written without negative exponent.
I am aware that [MATH] \frac{x^{-3}}{x^{5}} [/MATH] can be written as [MATH] x^{-3-5} [/MATH] and this yields [MATH] \frac{1}{x^{8}} [/MATH].
Another way is to write it like this:
[MATH]\frac{2*\frac{1}{x^3}}{x^{5}} [/MATH]
According to the solution this results in [MATH]\frac{2}{\dfrac{x^{3}}{x^{5}}} = \frac{2}{x^{3} * x^{5}} = \frac{2}{x^{8}} [/MATH]
These last two steps confuse me. Why can you write this in such a way under each other?
I always multiplied double-fractions by the inverse; in my understanding this would be 2/x^3 * x^5 /1 = 2x^5 / x^3 , but this seems to be wrong.
I do not know, how to get the same result (2/x^8) using the long way.
Where is my reasoning error?
I have difficulties with a double fraction.
[MATH] \frac{2x^{-3}}{x^{5}} [/MATH] should be written without negative exponent.
I am aware that [MATH] \frac{x^{-3}}{x^{5}} [/MATH] can be written as [MATH] x^{-3-5} [/MATH] and this yields [MATH] \frac{1}{x^{8}} [/MATH].
Another way is to write it like this:
[MATH]\frac{2*\frac{1}{x^3}}{x^{5}} [/MATH]
According to the solution this results in [MATH]\frac{2}{\dfrac{x^{3}}{x^{5}}} = \frac{2}{x^{3} * x^{5}} = \frac{2}{x^{8}} [/MATH]
These last two steps confuse me. Why can you write this in such a way under each other?
I always multiplied double-fractions by the inverse; in my understanding this would be 2/x^3 * x^5 /1 = 2x^5 / x^3 , but this seems to be wrong.
I do not know, how to get the same result (2/x^8) using the long way.
Where is my reasoning error?