Write the series using sigma notation

What have you tried? How far have you gotten? Where are you stuck?

Please be specific.

Thank you.

Eliz.
 
I notice that when i subtract one term from the next, I get this
2+5+10+17+26+27
3 5 7 9 11
2 2 2 2
This is where i am stuck
I dont know how I should i write it in the notation
thanks
 
Hello, bryan-duong!

I notice that when i subtract one term from the next, I get this:
    2      5      10    17    26    37\displaystyle \;\;2\;\;\;5\;\;\;10\;\;17\;\;26\;\;37
        3      5      7      9    11\displaystyle \;\;\;\;3\;\;\;5\;\;\;7\;\;\;9\;\;11
            2      2     2     2\displaystyle \;\;\;\;\;\;2\;\;\;2\;\:\;2\;\;\:2
Since the second differences are constant, the function is a quadratic (second degree).

You can "eyeball it . . . note that every term is one more than a square:
    12+1,  22+1   32+1,  42+1,  52+1,  62+1\displaystyle \;\;1^2\,+\,1,\;2^2\,+\,1\,\;3^2\,+\,1,\;4^2\,+\,1,\;5^2\,+\,1,\;6^2\,+\,1

The general term is: n2+1\displaystyle \,n^2\,+\,1

In sigma notation: \(\displaystyle \L\,\sum^6_{n=1}(n^2\,+\,1)\)
 
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