Write the expression with only positive exponents

[sonyamarie09]

b^(13/14) * b^(-5/4)

What I've done is added the exponents to get a common denominator, so what I have is b^(26/28) * b^(-35/28) = b^(-9/28) and then that would equal 1/b^(9/28)
But it keeps telling me that my answer is wrong. I don't know what I'm doing wrong. Please help!

 

[daon2]

Your answer is correct. It is possible that the software (whatever that may be) evaluating your answer expects something different. Did you try:

1. \(\displaystyle b^{-9/28}\)

2. \(\displaystyle \displaystyle \sqrt[28]{b^{-9}}\)

3. \(\displaystyle \displaystyle \dfrac{1}{\sqrt[28]{b^{9}}}\)

 

[Deleted member 4993]

b^(13/14) * b^(-5/4)

What I've done is added the exponents to get a common denominator, so what I have is b^(26/28) * b^(-35/28) = b^(-9/28) and then that would equal 1/b^(9/28)
But it keeps telling me that my answer is wrong. I don't know what I'm doing wrong. Please help!

If that is what you have been asked to do - you have done it correctly.

Also try \(\displaystyle \displaystyle \left [ \frac{1}{b}\right ]^{\frac{9}{28}}\)

 

[sonyamarie09]

I guess my issue is that it says to "Simplify your answer. Type exponential notation with positive exponents."
That doesn't make sense to me, because even if I did that, I would have to use a negative exponent, wouldn't I?
9/28=0.32, so it would be 3.2x10^-1 in the denominator?

 

[lookagain]

I guess my issue is that it says to "Simplify your answer.
Type exponential notation with positive exponents."
That doesn't make sense to me, because even if I did that,
I would have to use a negative exponent, wouldn't I?

9/28=0.32, \(\displaystyle \ \ \ \) They're not equal to each other.

so it would be 3.2x10^-1 in the denominator?

.