Question: Write f' in terms of g' in each case. Simplify your answers.
\(\displaystyle \L\\\begin{array}{l}
f(x) = x^3 g(e^{2x} ) \\
g(x) = e^{2x} \\
g'(x) = 2e^{2x} \\
f'(x) = \frac{d}{{dx}}x^3 g + x^3 \frac{d}{{dx}}g \\
f'(x) = 3x^2 e^{2x} + x^3 e^{2x} 2 \\
f'(x) = x^2 e^{2x} \left( {3 + 2x} \right) \\
\end{array}\)
My problem is I think I have gone of on my own little tangent. I would appreciate some direction if this is wrong.
Thanks, Sophie
\(\displaystyle \L\\\begin{array}{l}
f(x) = x^3 g(e^{2x} ) \\
g(x) = e^{2x} \\
g'(x) = 2e^{2x} \\
f'(x) = \frac{d}{{dx}}x^3 g + x^3 \frac{d}{{dx}}g \\
f'(x) = 3x^2 e^{2x} + x^3 e^{2x} 2 \\
f'(x) = x^2 e^{2x} \left( {3 + 2x} \right) \\
\end{array}\)
My problem is I think I have gone of on my own little tangent. I would appreciate some direction if this is wrong.
Thanks, Sophie