Write eqn of line containing (2, 7) and parallel to x+5y = 3

[gibbsjx]

Write an equation of the line containing the given point and parallel to the given line. Express your answer in the form y=mx+b - (2,7); x+5y = 3

I have subtracted x from the 5y side to get to - 5y = -x+3
Then to get rid of the 5, I divided by 5 to get - y = -x over 5 + 3
I then substituted (2,7) into the equasion to get - 7 = (1/5x2) + B or 7 = -2/5 + B
I come up with 35/5 + 2/5 = B

I hope this is clear, am I on the right track?

 

[Loren]

Kinda. The line you are after has the same slope as the given line. It also passes through the given point. Are you familiar with the point-slope form? \(\displaystyle y-y_1=m(x-x_1)\)

 

[Denis]

x+5y = 3
I have subtracted x from the 5y side to get to - 5y = -x+3
Then to get rid of the 5, I divided by 5 to get - y = -x over 5 + 3
I then substituted (2,7) into the equasion to get - 7 = (1/5x2) + B or 7 = -2/5 + B
I come up with 35/5 + 2/5 = B

RELAX! You've made a few "sign" errors...
after subtracting x: 5y = -x + 3
after dividing by 5: y = (-1/5)x + 3/5

"m" and "b" are now glaring at you: see them?