Write e^(-2) = 0.1353 in logarithmic form: e=log_-2(0.1353)?

[charlesjoy]

Good morning. Can you please verify if I did this correctly?

e^-2 = 0.1353

e=log 0.1353
-2

 

[Deleted member 4993]

Re: Write in logaqrithmic form

Good morning. Can you please verify if I did this correctly?

e^-2 = 0.1353

e=log 0.1353 <<< Incorrect
-2

$\displaystyle e^{-2} \, = \, 0.1353$

$\displaystyle log_e(e^{-2}) \, = \, log_e(0.1353)$

$\displaystyle -2 \, = \, log_e(0.1353)$

 

[charlesjoy]

Re: Write in logaqrithmic form

Thank you very much.