Megan left Seattle at 4:34 p.m. and traveled at a rate of thirty-one kph more than two times the speed of Isaac, who left at the same time but in the opposite direction. By the time it was 5:47 p.m., they were 133 kilometers apart. What was Megan's speed?
word problems!!!!!!!!!!!
- Thread starter nick29
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They're going in opposite directions, so their distances are additive. Use the standard "uniform rate" equation, "d = rt".
. . . . .isaac:
. . . . .rate: r
. . . . .time: 1 + 13/60
. . . . .distance: (1 + 13/60)r
. . . . .megan:
. . . . .rate: 2r + 31
. . . . .time: 1 + 13/60
. . . . .distance: ...?
Complete the table. Add the two "distance" expressions, and set equal to the given total distance. Solve for r; back-solve for the requested information.
Eliz.
. . . . .isaac:
. . . . .rate: r
. . . . .time: 1 + 13/60
. . . . .distance: (1 + 13/60)r
. . . . .megan:
. . . . .rate: 2r + 31
. . . . .time: 1 + 13/60
. . . . .distance: ...?
Complete the table. Add the two "distance" expressions, and set equal to the given total distance. Solve for r; back-solve for the requested information.
Eliz.