jhawk555 said:
Bart has 3 investments totaling $110,000. These investments earn interest at 6%, 8%, and 10% respectively. Bart's total income from these investments is $9400. The income from the 10% investment exceeds the total from the other two investments by $600. Find out how much Bart has invested at 6%.
Well....that's a bit better. But, you still didn't tell us what each variable represents.
So, I'll tell you what I would do (your opinion may differ!):
Let x = amount invested at 6%
Let y = amount invested at 8%
Let z = amount invested at 10%
Total amount invested is $110,000
So,
x + y + z = 110000
Total income from all three investments is $9400.
So,
.06x + .08y + .1z = 9400
Income from 10% investment (z) exceeds the income from the other two investments (x and y) by $600.
This means that if you subtract the total of the interest earned on the 6% and 8% investments FROM the interest earned on the 10% investment, you should get 600.
.1z - (.06x + .08y) = 600
Now, you can take it from here.....
You've got three equations in three variables:
x + y + z = 110000
.06x + .08y + .1z = 9400
.1z - (0.06x + 0.08y) = 600
Solve by your favorite method.