Word problems and quadratic equations!

[Richay]

Find three consecutive intergers such that the product of the first and the second is equal to the product of -6 and the third.
Answer in the from: a, b, c and d, e, f (smallest to largest)

This is too hard for me. I understand some of it..

x[x+1] = -6[x+2]

x^2 + x = -6x -12

x^2+7x+12=0

[x+3][x+4]=0

x=-3 and -4
ABC = -4, -3, -2?

Now what about DEF? Somebody help me out.

 

[pka]

It seems to me as if you have answered the question correctly! PERIOD.
You have given the same answer to both questions.
And you are correct.

 

[Richay]

It seems to me as if you have answered the question correctly! PERIOD.
You have given the same answer to both questions.
And you are correct.

Really? Oh do you know how would I properly write the answer?

 

[pka]

Find three consecutive intergers such that the product of the first and the second is equal to the product of -6 and the third.
Answer in the from: a, b, c and d, e, f (smallest to largest)

The integers are –4, -3, & -2.
(smallest to largest) is –4, -3, & -2.
DONE!

 

[Denis]

Hmmm...solution is x = -3 or x = -4; so:

a,b,c = -3, -2, -1
d,e,f = -4, -3, -2

check:
-3 * -2 = 6 ; -6 * -1 = 6
-4 * -3 = 12 ; -6 * -2 = 12

 

[Richay]

Hmm I see. Thanks guys.

The teacher keeps telling me I'm wrong. Ugh guess I'll have to stay after school to prove I'm correct :lol: