Word Problem

thechicinnovation

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Jul 5, 2012
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Find a two digit number that is 4 times bigger than the sum of its digits and the product of the digits times three equals the two digit number.
I thought that it would be:
x+y=4(x+y)
x+y=3(xy)
However, my answer doesn't work out...
 
Find a two digit number that is 4 times bigger than the sum of its digits and the product of the digits times three equals the two digit number.
I thought that it would be:
x+y=4(x+y)
x+y=3(xy)
However, my answer doesn't work out...
I assume you are dealing with our standard "base 10" number system in which 14= 10+ 4= 10(1)+ 4, 37= 30+ 7= 10(3)+ 7, 42= 40+ 2= 10(4)+ 2, etc. That is, the "two digit number" with digits a and b ("ab") is equal to 10a+ b. Saying that the two digit number "xy", "is 4 times bigger than the sum its digits" means that 10x+ y= 4(x+ y) and "the product of the digits times three equals the two digit number" means that 10x+ y= 3(xy). Solve those equations.
 
Thanks

I assume you are dealing with our standard "base 10" number system in which 14= 10+ 4= 10(1)+ 4, 37= 30+ 7= 10(3)+ 7, 42= 40+ 2= 10(4)+ 2, etc. That is, the "two digit number" with digits a and b ("ab") is equal to 10a+ b. Saying that the two digit number "xy", "is 4 times bigger than the sum its digits" means that 10x+ y= 4(x+ y) and "the product of the digits times three equals the two digit number" means that 10x+ y= 3(xy). Solve those equations.
so, the answer is 24?
 
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