Let \(\displaystyle x\) = first integer, \(\displaystyle x+1\) = next integer.
. . \(\displaystyle \underbrace{\text{ Product of the two integers }}_{x(x+1)} \underbrace{\text{ is }}_{=} \underbrace{\text{ 8 times }}_{8 \times} \underbrace{\text{ their sum }}_{x+(x+1)} \underbrace{\text{ minus 8 }}_{-\;8}\)
\(\displaystyle \text{The equation is: }\;x(x+1) \;=\;8(2x+1) - 8\)
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