Word problem

[Kimbers0812]

Can somebody please help me....

It takes one pipe 3/5 as long as it takes another pipe to fill a tank. If the two pipes together fill the tank in 45 minutes, how long does it take each pipe to fill the tank?

Thanks! :?:

 

[galactus]

Try seting it up as the amount the pipes fill in 1 minute.

\(\displaystyle \L\\\frac{3}{5t}+\frac{1}{t}=\frac{1}{45}\)

Solve for t and find the times for each pipe by itself.

 

[Kimbers0812]

I'm still confused.

 

[Mrspi]

Can somebody please help me....

It takes one pipe 3/5 as long as it takes another pipe to fill a tank. If the two pipes together fill the tank in 45 minutes, how long does it take each pipe to fill the tank?

Thanks! :?:

let x = time (in minutes) for one pipe to fill the tank. In 1 minute, this pipe fills 1/x of the tank. In 45 minutes, this pipe fills 45/x of the tank.

The second pipe takes 3/5 as long as the first pipe. If the first pipe takes x minutes to fill the tank, then the second pipe takes (3/5)x minutes to fill the tank. In 1 minute, the second pipe fills 1 / (3/5)x of the tank. In 45 minutes, the second pipe fills 45 / (3/5)x of the tank.

If the two pipes are working together for 45 minutes,

part done by first pipe + part done by second pipe = whole job

45 / x + 45 / (3/5)x = 1

Multiply numerator and denominator of the second fraction by (5/3):

45 / x + [45 * (5/3) / (5/3)*(3/5)x] = 1

45 / x + 75 / x = 1

Solve this for x.....that will be the number of minutes it takes the first pipe to fill the tank by itself.

(3/5)x is the number of minutes it takes the second pipe to fill the tank by itself.