Word Problem

cprochilo

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Sep 15, 2005
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An object launched upward with an initial velocity of 9.8m/s from a height of 73.5m will have a height of s(t)=(-4.9t^2)+ 9.8t + 73.5m, where s is in meters and t is in seconds. How long will it take the object to hit the ground.

I recieved this homework problem and I can't figure out how to start it, I was wondering if anyone could at least get me on the right track. Thank you
 
Hint: What is the value of the "height" when the object hits the ground?

Eliz.
 
Re: Calculus Word Problem

Hello, cprochilo!

This isn't really a Calculus problem . . .

An object launched upward with an initial velocity of 9.8m/s from a height of 73.5m
will have a height of: s(t)=4.9t2+9.8t+73.5\displaystyle \,s(t)\:=\:-4.9t^2\,+\, 9.8t\,+\,73.5,
where s\displaystyle s is in meters and t\displaystyle t is in seconds.
How long will it take the object to hit the ground?
What is the object's height when it hits the ground?
    \displaystyle \;\;Obviously, the height is 0 (zero).

Very well, when is the height equal to 0?

Let's find out: 4.9t2+9.8t+73.5=0\displaystyle \,-4.9t^2\,+\,9.8t\,+\,73.5\:=\:0 . . . solve for t\displaystyle t.
 
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