word problem with inequality

karalynn

New member
Joined
Oct 15, 2007
Messages
2
Bay insurance offers two plans. Plan A: Pay the first $50 of bills and 20% of all bills after that. Plan B: Pay the first $250 of bills and 10% of all bills after that. For what amount of money would plan B save more money? Write an algebraic inequality for the following and solve.
 
karalynn said:
Bay insurance offers two plans. Plan A: Pay the first $50 of bills and 20% of all bills after that. Plan B: Pay the first $250 of bills and 10% of all bills after that. For what amount of money would plan B save more money? Write an algebraic inequality for the following and solve.

Please show us your work/thoughts and exactly where you are stuck - so that we can help you properly.
 
I know I need to set up an algebraic inequality. If I knew how much the bills were I would subtract 50 from it and then multiply my answer by .20 and then do the same with plan B.
x-50 and x-250 but I don't know what to do with the percents.
 
Bay insurance offers two plans. Plan A: Pay the first $50 of bills and 20% of all bills after that. Plan B: Pay the first $250 of bills and 10% of all bills after that. For what amount of money would plan B save more money? Write an algebraic inequality for the following and solve.

Plan A pays 50 + .20B

Plan B pays 250 + .10B

There is some amount of bills, B, that would result in the same cost.

What amount of bills would you imagine would be the break even point between these two plans, i.e., result in the same payout? How might you determine that amount?

Which plan would then result in less cost?
 
Top