word problem using pythagorean theorom

kkhewett

New member
Joined
Jan 18, 2010
Messages
5
Rectangular stage. One side of a rectangular stage is
2 meters longer than the other. If the diagonal is 10 meters,
then what are the lengths of the sides?
I set up the equation as such:
x^2 + (x+2)^2 = 10^2
x^2 +x^2 + 2(x+2) = 100
2x^2 + 2x+4 = 100
2x^2 + 2x - 96= 0
x^2 +x - 48 = 0
now here is where I am totally stuck can you guys help???
 
kkhewett said:
Rectangular stage. One side of a rectangular stage is
2 meters longer than the other. If the diagonal is 10 meters,
then what are the lengths of the sides?
I set up the equation as such:
x^2 + (x+2)^2 = 10^2
x^2 +x^2 + 2(x+2) = 100
NO. (x+2)^2 = (x+2) times (x+2) = x^2 + 4x + 4

So equation will be: x^2 + 2x - 48 = 0
Solve for x
 
actually after wrestling with this problem a while I finally saw the clarity of my demise!!!
I got it
the answer is
x=6 and x=8
sides are 6m and 8m!! wehew!!!!!
 
Top