msosebee said:
sorry Im new
yea i have
-.27+/- (square root)-.2711 / .02
..i cannot figure out what to do with the square root of -.2711
I'm not sure how you came up with that.....
w(x) = -0.01x[sup
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vedmmx5]2[/sup
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vedmmx5] + 0.27x + 8.6 can be used to estimate the number of self-employed workers in the United States, in millions, x years after 1980
Ok...you are looking for the value of x (which will be the
number of years after 1980 when the value of the function (number of self-employed workers) is 10.12 million.
Substitute 10.12 for w(x):
10.12 = -0.01x[sup
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vedmmx5]2[/sup
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vedmmx5] + 0.27x + 8.6
Since this is a quadratic equation, let's get one side to be 0. Subtract 10.12 from both sides:
10.12 - 10.12 = -0.01x[sup
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vedmmx5]2[/sup
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vedmmx5] + 0.27x + 8.6 - 10.12
0 = -0.01x[sup
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vedmmx5]2[/sup
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vedmmx5] + 0.27x - 1.52
Hmmmm...I'd sure like that equation a LOT better if the coefficient of x[sup
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vedmmx5]2[/sup
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vedmmx5] was POSITIVE, and if there were no decimals. Let's see...what if I multiply both sides by -100?
-100(0) = -100(-0.01x[sup
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vedmmx5]2[/sup
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vedmmx5] + (-100)(0.27x) - (-100)(1.52)
0 = x[sup
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vedmmx5]2[/sup
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vedmmx5] - 27x + 152
Now, apply the quadratic formula. You should NOT get a negative number under the radical sign...in fact, you'll get a VERY NICE number.
OH....and don't forget...."x" is the number of years AFTER 1980. So, whatever value(s) you get for x will need to be ADDED to 1980 to give you the year(s) when this number of workers are self-employed.